Functional Skills: Surface Area

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Surface Area of 3D Shapes

The surface area of any 3D shape is the areas of all faces of the shape added together. You can use nets to help find the surface area.

Make sure you are happy with the following topics before continuing.

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Calculating the Surface Area

You may be given the area of each face of a 3D shape, or you will more likely be given the dimensions and have to work out the area of each face individually.

Example: Calculate the surface area of the cuboid.

The area of the front face and back face are both 8×3=24 cm2textcolor{blue}{8} times textcolor{blue}{3} = 24 text{ cm}^2

The area of the side faces are both 5×3=15 cm2textcolor{blue}{5} times textcolor{blue}{3} = 15text{ cm}^2

The area of the top face and bottom face are both 8×5=40 cm2textcolor{blue}{8} times textcolor{blue}{5} = 40text{ cm}^2

Therefore, the total surface area is

(2×24)+(2×15)+(2×40)=48+30+80=158 cm2(2 times 24) + (2 times 15) + (2 times 40) = 48 + 30 + 80 = 158 text{ cm}^2

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Using Nets to find the Surface Area

You can use nets to help find the surface area. This will help when calculating the surface area of all 3D shapes, especially prisms and cylinders.

Example: Calculate the surface area of the cylinder.

Give your answer to the nearest whole number.

Use π=3.14pi = 3.14

 

You can draw the net of this cylinder to help:

The net has two circles of radius 4textcolor{red}{4} cm, and a rectangle of width 5textcolor{blue}{5} cm and length which is equal to the circumference of the circles.

First, calculate the circumference of the circle:

circumference =πd=2πr=2×3.14×4=25.12= pi d = 2 pi r = 2 times 3.14 times textcolor{red}{4} = 25.12 cm

Then, calculate the areas of the faces:

area of rectangle =25.12×5=125.6= 25.12 times textcolor{blue}{5} = 125.6 cm2^2

area of circle =πr2=3.14×42=50.24=pi r^2 = 3.14 times textcolor{red}{4}^2 = 50.24 cm2^2

So, add the areas of all the faces together, to find the surface area of the cylinder:

surface area of cylinder =50.24+50.24+125.6=226.08=226= 50.24 + 50.24 + 125.6 = 226.08 = 226 cm2^2

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Example 1: Surface Area of a Pyramid

Calculate the surface area of the pyramid.

[4 marks]

All 44 triangular faces are equal.

So, we can calculate the area of one triangle and multiply it by 44 to get the area of all of them.

Area of triangle =12×b×h=12×5×8=20= dfrac{1}{2} times b times h = dfrac{1}{2}times5times8=20 cm2^2

Therefore, the area of all 44 triangles is

4×20=804times20=80 cm2^2

Now, we need to find the area of the square base,

Area of base =5×5=25=5 times 5=25 cm2^2

Therefore, the surface area is the area of each face added together:

Total surface area =25+80=105=25+80=105 cm2^2

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Example 2: Surface Area of a Sphere

Calculate the surface area of the sphere with a radius of 12 cm.

[2 marks]

Use \pi = 3.14

The surface area of a sphere can be calculated by substituting the radius into this formula.

\text{Surface Area} = 4 \times \pi \times \text{radius}^{2}

\text{Surface Area} = 4 \times 3.14 \times 12^{2} = 1808.64\text{ cm}^{2}

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Functional Skills: Surface Area Example Questions

Question 1: A cube has sides of length 77 cm.

Calculate the surface area of the cube.

[2 marks]

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The area of one square face is

 

7×7=497 times 7 = 49 cm2^2

 

Therefore, since a cube has 66 square faces, the surface area is

 

6×49=2946 times 49 = 294 cm2^2

Question 2: Below is a cuboid with length 66 mm, width 2.52.5 mm, and height 44 mm.

Calculate the surface area of the cuboid.

[3 marks]

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Area of front face:

 

4×2.5=104times2.5=10 mm2^2

 

Therefore, the back face also has area 1010 mm2^2

 

Area of right side face:

 

6×4=246times4=24 mm2^2

 

Therefore, the left side face also has area 2424 mm2^2

 

Area of top face:

 

6×2.5=156times2.5=15 mm2^2

 

Therefore, the bottom face also has area 1515 mm2^2

 

Total surface area:

 

10+10+24+24+15+15=9810+10+24+24+15+15=98 mm2^2

Question 3: Calculate the surface area of the prism in the diagram below.

[4 marks]

 

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The area of the front triangular face is

 

12×6×4=12dfrac{1}{2} times 6 times 4 = 12 cm2^2

 

The area of the back triangular face is therefore 1212 cm2^2 also.

 

The area of a slanted rectangular face is

 

11×5=5511 times 5 = 55 cm2^2

 

The area of the other slanted rectangular face is also 5555 cm2^2

 

The area of the rectangular base is

 

11×6=6611 times 6 = 66 cm2^2

 

Therefore, the total surface area is

12+12+55+55+66=20012 + 12 + 55 + 55 + 66 = 200 cm2^2

Additional Resources

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Exam Tips Cheat Sheet

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Formula Booklet

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Specification Points Covered

L2.17 – Use formulae to find volumes and surface areas of 3-D shapes including cylinders (formulae to be given for 3-D shapes other than cylinders)

Functional Skills: Surface Area Worksheet and Example Questions

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Surface Area L2

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